(1/(x^2+2x+4))-(1/(x^2+2x+5))=1/12. Created by mrshaurman. algebra-ru

12...

армения20171 1/(х²+2х+4)-1/(х²+2х+5)=1/12

х²+2х+4=у≠0;

1/у-1/(у+1)=1/12;у+1≠0
12(у+1)-12у-у(у+1)=0
12у+12-12у-у²-у=0
у²+у-12=0
Д=1+48=49=7²
у=(-1±7)/2
у1=-4;у2=3

1)х²+2х+4=-4
х²+2х+8=0
Д=4-32=-28<0
х€∅

2)х²+2х+4=3
х²+2х+1=0
(х+1)²=0

х+1=0
х=-1

ответ -1

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