March 2022 0 5 Report
1)2log2 (-x)=1+log2 (x+4)
2)Log^2(9x)+log^2(3x)=1 (основание 3)
3)log2(9-2^x)=3^log3(3-x)
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.
More Questions From This User See All
log4(2x+2)=0...
Answer
log5x2 4gt0 pomogite pozhalujsta ne ponimayu chto delat s 0
Answer
1)lg(x-2)-0.5lg(3x-6)=lg2 2)log0.5*log5*(x^2-4)>0 3)2log2(x-2)+log0.5(x-3)>...
Answer
3u vtorogo h
Answer
pomogite pozhalujsta takoj vopros 1kak ponyat kakim osnovaniem i kakoj kislot
Answer
1)logx-1(2x^2-5x-3)=2 2)lg(x-2)-0.5lg(3x-6)=lg...
Answer
Log2x(x^2+x-2)=1...
Answer

Helpful Links

Helpful Social

Copyright © 2025 SCHOLAR.TIPS - All rights reserved.