[tex]\displaystyle \left \{ {{y+12x=2} \atop {9y-12x=4}} \right. \\\\\left \{ {{12x=2-y} \atop {9y-12x=4}} \right. \\\\9y-(2-y)=4\\\\y=\frac{3}{5}=0,6\\[/tex]
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[tex]\displaystyle \left \{ {{y+12x=2} \atop {9y-12x=4}} \right. \\\\\left \{ {{12x=2-y} \atop {9y-12x=4}} \right. \\\\9y-(2-y)=4\\\\y=\frac{3}{5}=0,6\\[/tex]
9y-12x=4 => 9y-12x=4 =>9y-2+y=4
10y=4+2
10y=6
y= 6/10 или 0,6