[tex]\displaystyle \left \{ {{\frac{x}{2}+\frac{y}{2}=2 } \atop {\frac{x}{12}+\frac{y}{6}=2 }} \right.\\ \\(x+y)-(x+2y)=4-24\\-y=-20\\y=20\\ x+20=4\\x=-16\\(x,y)=(-16,20)[/tex]

Ответ:

[tex]\boldsymbol{(-16;20)}[/tex]

Объяснение:

[tex]\displaystyle \left \{{{\displaystyle\frac{x}{2}+\frac{y}{2} =2} \atop {\displaystyle\frac{x}{12}+\frac{y}{6}=2 }} \right. \Leftrightarrow \left \{{{\displaystyle\frac{x}{2}+\frac{y}{2^{}} =2|*2} \atop {\displaystyle\frac{x}{12}+\frac{y^{(2}}{6}=2 | *12}} \right. \Leftrightarrow \left \{ {{x+y=4} \atop {x+2y=24}} \right.[/tex]

[tex](x+y)-(x+2y)=4-24\\x+y-x-2y=-20\\(x-x)+(y-2y)=-20\\-y=-20|*(-1)\\\boldsymbol{y=20}[/tex]

[tex]x+2y=24\\x+2*20=24\\x+40=24\\x=24-40\\\boldsymbol{x=-16}[/tex]