13+x^2(x-9) < (x - 3)^3+11 26+(2+x)^3 < x^2(6+x) 3x-x^2(15+x) > -(x+5)^3-4x (4+x)^3 - 6x < x^2(x+12)+1. Created by ketiemelyanenk. algebra-ru

13+x*2x-1813+3x -1813+18=3x3x=31x=31:33x-9+113x=-9+113x=2x=3:2x=1.526+6+3x32=3xx=32:3x*12+2x3x=12x=12:3x=43x-x*30+2x2x+2x*304x=30x=30:4x=7.53x-15-4xx=-1512+3x-6x 3x=12x=12:3x=4x*2x+13+13x+13x=13:3

13+x^2(x-9) < (x - 3)^3+11 26+(2+x)^3 < x^2(6+x) 3x-x^2(15+x)

ketiemelyanenk @ketiemelyanenk

August 2021 1 16 Report

13+x^2(x-9) < (x - 3)^3+11
26+(2+x)^3 < x^2(6+x)
3x-x^2(15+x) > -(x+5)^3-4x
(4+x)^3 - 6x < x^2(x+12)+1

Answers & Comments

Morozova134 13+x*2x-18
13+3x -18
13+18=3x
3x=31
x=31:3
$x = \frac{31}{3} = 10 \frac{1}{3}$
3x-9+11
3x=-9+11
3x=2
x=3:2
x=1.5

26+6+3x
32=3x
x=32:3
$x = 10 \frac{2}{3}$
x*12+2x
3x=12
x=12:3
x=4

3x-x*30+2x
2x+2x*30
4x=30
x=30:4
x=7.5

3x-15-4x
x=-15

12+3x-6x
3x=12
x=12:3
x=4

x*2x+13+1
3x+13
x=13:3
$x = 4 \frac{1}{3}$

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