Ответ: ∡DBF=100°
Объяснение:
ΔAHB=ΔFHB ( катет-катет)
=> ∡ABH=∡FBH =180°-∡ABC =40°
=> ∡ABF=2·∡ABH=2·40°=80°
=> ∡DBF=180°-∡ABF= 180°-80°=100°
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Ответ: ∡DBF=100°
Объяснение:
ΔAHB=ΔFHB ( катет-катет)
=> ∡ABH=∡FBH =180°-∡ABC =40°
=> ∡ABF=2·∡ABH=2·40°=80°
=> ∡DBF=180°-∡ABF= 180°-80°=100°