[tex]\displaystyle\bf\\b_{1} =-1\\\\b_{2} =2\\\\q=b_{2} : b_{1} =2:(-1)=-2\\\\\\S_{8} =\frac{b_{1} \cdot(q^{8}-1) }{q-1}=\frac{-1\cdot \Big[(-2)^{8}-1\Big] }{-2-1}=\frac{256-1}{3} = 85[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]\displaystyle\bf\\b_{1} =-1\\\\b_{2} =2\\\\q=b_{2} : b_{1} =2:(-1)=-2\\\\\\S_{8} =\frac{b_{1} \cdot(q^{8}-1) }{q-1}=\frac{-1\cdot \Big[(-2)^{8}-1\Big] }{-2-1}=\frac{256-1}{3} = 85[/tex]