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Кастиэль21
@Кастиэль21
November 2021
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16(x-y)^2-25(x+y)^2
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manyny06
Verified answer
16(х-у)² - 25(х+у)² = (4(х-у))² - (5(х+у))² = (4(х-у) - 5(х+у) (4(х-у) + 5(х+у)) =
(4х-4у-5х-5у)(4х-4у+5х+5у) = (-х-9у)(9х+у) = -(х+9у)(9х+у)
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Answers & Comments
Verified answer
16(х-у)² - 25(х+у)² = (4(х-у))² - (5(х+у))² = (4(х-у) - 5(х+у) (4(х-у) + 5(х+у)) =(4х-4у-5х-5у)(4х-4у+5х+5у) = (-х-9у)(9х+у) = -(х+9у)(9х+у)