8+2√7/1+√7 Помогите кто может,пожалуйста. Created by AnnaYudina. algebra-ru

1+√7 Помогите кто может,пожалуйста...

azikt

$\frac{8+2\sqrt{7}}{1+\sqrt{7}}=\frac{(8+2\sqrt{7})(1-\sqrt{7})}{(1+\sqrt{7})(1-\sqrt{7})}=\frac{8-8\sqrt{7}+2\sqrt{7}-2(\sqrt{7})^{2}}{1-(\sqrt{7})^{2}}=
 
=\frac{8-6\sqrt{7}-14}{1-7}=\frac{-6-6\sqrt{7}}{-6}=\frac{-6(1+\sqrt{7})}{-6}=1+\sqrt{7}$

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ATLAS

Verified answer

8 +2√7+√7=8+3√7 вроде так должно получиться

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