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Deygvgycch
@Deygvgycch
July 2023
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BomBom1609
Ответ:
x²-2x-3=0
D=b²-4ac=4-(-12)=4+12=16
x1=[tex]\frac{-b+\sqrt{D} }{2a}[tex]=[tex]\frac{2+4}{2}[tex]=[tex]\frac{6}{2}[tex]=3
x2=[tex]\frac{-b-\sqrt{D} }{2a}[tex]=[tex]\frac{2-4}{2}[tex]=[tex]\frac{-2}{2}[tex]=-1
3+(-1)=2
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BomBom1609
мда уж, извиняюсь, знания почему-то сломали объяснение...
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Answers & Comments
x²-2x-3=0
D=b²-4ac=4-(-12)=4+12=16
x1=[tex]\frac{-b+\sqrt{D} }{2a}[tex]=[tex]\frac{2+4}{2}[tex]=[tex]\frac{6}{2}[tex]=3
x2=[tex]\frac{-b-\sqrt{D} }{2a}[tex]=[tex]\frac{2-4}{2}[tex]=[tex]\frac{-2}{2}[tex]=-1
3+(-1)=2