[tex] \frac{7q}{4x} - \frac{3q}{4x} = \frac{4q}{4x} = \frac{q}{x} [/tex]

[tex] \frac{d + 4}{9} + \frac{5 - d}{9} = \frac{d + 4 + 5 - d}{9} = \frac{9}{9} = 1[/tex]

[tex] \frac{5f}{2c} - \frac{3f}{2c} = \frac{5f - 3f}{2c} = \frac{2f}{2c} = \frac{f}{c} [/tex]

[tex] \frac{ {x}^{2} }{x - 5} - \frac{25}{x - 5} = \frac{ {x}^{2} - 25 }{x -5 } = \frac{(x - 5)(x + 5)}{x - 5} = x + 5[/tex]

[tex] \frac{49}{7 - m} - \frac{ {m}^{2} }{7 - m} = \frac{49 - {m}^{2} }{7 - m} = \frac{(7 - m)(7 + m)}{7 - m} = 7 + m[/tex]

[tex] \frac{5x}{x - y} + \frac{5y}{y - x} = \frac{5x}{x - y} - \frac{5y}{x - y} = \frac{5x - 5y}{ x - y} = \frac{5(x - y)}{x - y} = 5[/tex]

[tex] \frac{ {y}^{2} }{y + 4} - \frac{16}{y + 4} = \frac{ {y}^{2} - 16 }{y + 4} = \frac{(y - 4)(y + 4)}{y + 4} = y - 4[/tex]

[tex] \frac{3}{ {(b - 1)}^{2} } + \frac{6}{ {(1 - b)}^{2} } = \frac{9}{ {(b - 1)}^{2} } [/tex]

[tex] \frac{ {x}^{2} + 1 }{x - 3} - \frac{10}{x - 3} = \frac{ {x}^{2} - 9 }{x - 3} = \frac{(x - 3)(x + 3)}{x - 3} = x + 3 \\ 97 + 3 = 100[/tex]

Телефон розряджається, тому не встигаю три останні зробити