Ответ:
[tex] \sqrt{5x + 1} = 1 - x \\ 5x + 1 = (1 - x)^{2} \\ 5x + 1 = 1 - 2x + {x}^{2} \\ 7x - {x}^{2} = 0 \\ x(7 - x) = 0 \\ [/tex]
x = 0
7 - x = 0
x = 7
x=0
Объяснение:
5x+1=1-2x+x²
5x=-2x+x²
5x+2x-x²=0
7x-x²=0
x•(7-x)=0
x=7
√5•0+1=1-0
√5•7+1=1-7
1=1
6= -6
x≠7
X=0
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Answers & Comments
Ответ:
[tex] \sqrt{5x + 1} = 1 - x \\ 5x + 1 = (1 - x)^{2} \\ 5x + 1 = 1 - 2x + {x}^{2} \\ 7x - {x}^{2} = 0 \\ x(7 - x) = 0 \\ [/tex]
x = 0
7 - x = 0
x = 7
Ответ:
x=0
Объяснение:
5x+1=1-2x+x²
5x=-2x+x²
5x+2x-x²=0
7x-x²=0
x•(7-x)=0
x=0
x=7
√5•0+1=1-0
√5•7+1=1-7
1=1
6= -6
x=0
x≠7
X=0