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olechka199812
@olechka199812
June 2022
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1)lgx+lg(x-1)=lg2
2)lg(5-x)+lgx=lg4
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Verified answer
1. lg(x*(x-1))=lg2
x^2-x=2
x^2-x-2=0
x1+x2=1
x1*x2=-2
x1=2,x2=-1, но нужно учесть, что число под знаком логарифма >0,подходит x=2
2.lg((5-x)*x)=lg4
5x-x^2-4=0
x^2-5x+4=0
x1+x2=5
x1*x2=4
x1=4,x2=1
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Answers & Comments
Verified answer
1. lg(x*(x-1))=lg2x^2-x=2
x^2-x-2=0
x1+x2=1
x1*x2=-2
x1=2,x2=-1, но нужно учесть, что число под знаком логарифма >0,подходит x=2
2.lg((5-x)*x)=lg4
5x-x^2-4=0
x^2-5x+4=0
x1+x2=5
x1*x2=4
x1=4,x2=1