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madammasha12
@madammasha12
August 2022
2
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1)Написать уравнение касательной
y=f(x)=x^2,x0=1
2)Найти промежутки монотонности:
y=x^2-5x+4
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NNNLLL54
Verified answer
1 votes
Thanks 1
sedinalana
Verified answer
1
y=x²,x0=1
y(1)=1
y`=2x
y`(1)=2
Y=1+2(x-1)=1+2x-2=2x-1 уравнение касательной
2
y=x²-5x=4
y`=2x-5=0
2x=5
x=2,5
_ +
-------------------(2,5)-------------------
убыв возр
0 votes
Thanks 0
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Answers & Comments
Verified answer
Verified answer
1y=x²,x0=1
y(1)=1
y`=2x
y`(1)=2
Y=1+2(x-1)=1+2x-2=2x-1 уравнение касательной
2
y=x²-5x=4
y`=2x-5=0
2x=5
x=2,5
_ +
-------------------(2,5)-------------------
убыв возр