1)Решите систему ур-й: X-3y=2 xy+y=6 Решите пожалуйста. Created by Saika16. algebra-ru

1)Решите систему ур-й: X-3y=2 xy+y=6 Решите пожалуйста...

Saika16 @Saika16

August 2022 1 6 Report

1)Решите систему ур-й:
X-3y=2
xy+y=6
Решите пожалуйста

Answers & Comments

xERISx

Verified answer

$\displaystyle\left \{ {{x-3y=2} \atop {xy+y=6}} \right. \ \ \ \Leftrightarrow\ \ \ \left \{ {{x=3y+2~~~~~~~} \atop {(3y+2)y+y=6}} \right.\\\\\\\left \{ {{x=3y+2~~} \atop {3y^2+3y=6}} \right.\ \ \ \Leftrightarrow\ \ \ \left \{ {{x=3y+2~~~} \atop {y^2+y-2=0}} \right.\\\\\\\left \{ {{x=3y+2~~~~~~~} \atop {(y+2)(y-1)=0}} \right.\ \ \ \Leftrightarrow\ \ \ \left \{ {{x=3y+2} \atop {\left [ {{y_1=-2} \atop {y_2=1~~}} \right. } \right.$

y₁ = -2; x₁ = 3·(-2) + 2 = -4

y₂ = 1; x₂ = 3·1 + 2 = 5

Ответ : (-4; -2), (5; 1)

5 votes Thanks 4

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