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ytukiya145
@ytukiya145
July 2022
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Доказать тождество: (1+sin2α+cos2α)/(1+sin2α-cos2α)=ctg α
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human00001
(1+sin2a+cos2a)/(1+sin2a-cos2a)=(1+2sina*cosa+cos^2 a-sin^2a)/(1+2sina*cosa-cos^2 a+sin^2 a)=(2sina*cosa+2cos^2a)/(2sina*cosa+2sin^2a)=2cosa(sina+cosa)/2sina(sina+cosa)
2 votes
Thanks 1
human00001
=ctga
ytukiya145
Спасибо огромное! если не сложно,посмотрите пожалуйста остальные задания(
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