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sjt25
@sjt25
July 2022
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1)t1=-2 2)t2=-1
x²+3-2=0 x²+3-1=0
помогите сделать проверку через дискриминант
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Msyчёба
1) а=1,в=3,с=(-2)
Д=В2-4ас
Д=9-4*1*(-2)
Д=17
t1=(-3)-17:2=-10
t2=(-3)+17:2=7
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Thanks 1
Msyчёба
2)а=1,в=3,с-(-1)
Msyчёба
Д=9-4*1*(-1)
Msyчёба
Д=13
Msyчёба
t1=(-3)-13:2
Msyчёба
t1=-8
Msyчёба
t2=(-3)+13:2
Msyчёба
t2=5
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Answers & Comments
Д=В2-4ас
Д=9-4*1*(-2)
Д=17
t1=(-3)-17:2=-10
t2=(-3)+17:2=7