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Sonkadg56ghh22
@Sonkadg56ghh22
July 2022
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1задание , прошу помощи
Буду очень благодарна )
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Paul2910
Решение приложено к снимку
1 votes
Thanks 1
sedinalana
Sin(3x-π/3)=1/√2
3x-π/3=π/4+2πk U 3x-π/3=3π/4+2πk
3x=7π/12+2πk U x=13π/12+2πk
x=7π/36+2πk/3 U x=13π/36+2πk/3,k=z
k=-1 x=7π/36-2π/3=(7π-24π)/36=-17π/36
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Answers & Comments
3x-π/3=π/4+2πk U 3x-π/3=3π/4+2πk
3x=7π/12+2πk U x=13π/12+2πk
x=7π/36+2πk/3 U x=13π/36+2πk/3,k=z
k=-1 x=7π/36-2π/3=(7π-24π)/36=-17π/36