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Sonkadg56ghh22
@Sonkadg56ghh22
July 2022
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Помогите решить уравнение
номер 1 ,буду очень благодарна
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rubilovalex
(2^-3)^x*2^x^2=2^-2; 2^(x^2-3x)=2^(-2); x^2-3x= -2; x^2-3x+2=0; D=(-3)^2-4*2=1; x1=(3-1)/2, x2=(3+1)/2. x1=1, x2=2. Ответ: x1=1, x2=2.
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rubilovalex
будут вопросы, пишите.
Sonkadg56ghh22
спасибо болшое )
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