[tex]\displaystyle\bf\\x^{2} +17x+16=0\\\\Teorema \ Vieta:\\\\x_{1} +x_{2} =-17\\\\x_{1} \cdot x_{2} =16\\\\x_{1} =-1\\\\x_{2} =-16[/tex]
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[tex]\displaystyle\bf\\x^{2} +17x+16=0\\\\Teorema \ Vieta:\\\\x_{1} +x_{2} =-17\\\\x_{1} \cdot x_{2} =16\\\\x_{1} =-1\\\\x_{2} =-16[/tex]