[tex]\displaystyle\bf\\x^{2} +19x+48=0\\\\D=19^{2} -4\cdot 48=361-192=169=13^{2} \\\\\\x_{1} =\frac{-19+13}{2} =\frac{-6}{2} =-3\\\\\\x_{2} =\frac{-19-13}{2} =\frac{-32}{2} =-16\\\\\\Otvet: \ -3 \ \ ; \ \ -16[/tex]