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LenaT
@LenaT
July 2022
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Помогите решить уравнение.
tgx+cos(3π/2 -2x)=0
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ресь
2cos2x = √3sin(3Π/2+x)
2cos2x = -√3cosx
cosx(2cosx +√3)=0
cosx=0 x=п/2+пk
cosx=-√3/2 x=±(п-п/6)+2пn=±5п/6+2пn k,n €Z
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Answers & Comments
2cos2x = -√3cosx
cosx(2cosx +√3)=0
cosx=0 x=п/2+пk
cosx=-√3/2 x=±(п-п/6)+2пn=±5п/6+2пn k,n €Z