Дана квадратичная функция f(x)=x^2+2 Найдите значения:
1) f(4)
2) f(-3)
3) f(-1/2)
4) f(-0,2)
f(4)=16+2=18
f(-3)=9+2=11
f(-1/2)=1/4+2=9/4
f(-0.2)=0.04+2=2.04
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f(4)=16+2=18
f(-3)=9+2=11
f(-1/2)=1/4+2=9/4
f(-0.2)=0.04+2=2.04