[tex]\displaystyle 1)3(2-x)-(5x+4)=0,4-16x\\6-3x-5x-4=0,4-16x\\2-8x=0,4-16x\\-8x+16x=0,4-2\\8x=-1,6\\x=-0,2\\\\2)2(3-5p)=4(1-p)-1\\6-10p=4-4p-1\\6-10p=3-4p\\-10p+4p=3-6\\-6p=-3\\\\p=\frac{1}{2}=0,5[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]\displaystyle 1)3(2-x)-(5x+4)=0,4-16x\\6-3x-5x-4=0,4-16x\\2-8x=0,4-16x\\-8x+16x=0,4-2\\8x=-1,6\\x=-0,2\\\\2)2(3-5p)=4(1-p)-1\\6-10p=4-4p-1\\6-10p=3-4p\\-10p+4p=3-6\\-6p=-3\\\\p=\frac{1}{2}=0,5[/tex]