[tex]\displaystyle 3(1-x)+5(x+2)=1-4x\\3-3x+5x+10=1-4x\\13+2x=1-4x\\2x+4x=1-13\\6x=-12\\x=-2[/tex]
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-3x+5x+4x=1-3-10
6x=-12
x=-2
[tex]\displaystyle 3(1-x)+5(x+2)=1-4x\\3-3x+5x+10=1-4x\\13+2x=1-4x\\2x+4x=1-13\\6x=-12\\x=-2[/tex]