По теореме Виета:
[tex]{x}^{2} + bx + c = 0 \\ x _{1} + x_{2} = - b \\ x _{1} x_{2} = c[/tex]
[tex]x_{1} + x_{2} = 6=-(-6) \\ x_{1} x_{2} = 4 \\ {x}^{2} - 6x + 4 = 0[/tex]
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По теореме Виета:
[tex]{x}^{2} + bx + c = 0 \\ x _{1} + x_{2} = - b \\ x _{1} x_{2} = c[/tex]
[tex]x_{1} + x_{2} = 6=-(-6) \\ x_{1} x_{2} = 4 \\ {x}^{2} - 6x + 4 = 0[/tex]