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bumblebee81
@bumblebee81
April 2023
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Зная, что cosx = -5/13 и π/2 ≤ x ≤ π, вычислите sin x/2
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fenix6810
Verified answer
=sqrt(9/13)
на π/2 ≤ x ≤ π, sinx>0
cosx=1-2sin^2x/2
sin^2(x/2)=(1-cosx)/2
sinx/2=sqrt((1+5/13)/2)=sqrt(18/26)=sqrt(9/13)
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Answers & Comments
Verified answer
=sqrt(9/13)на π/2 ≤ x ≤ π, sinx>0
cosx=1-2sin^2x/2
sin^2(x/2)=(1-cosx)/2
sinx/2=sqrt((1+5/13)/2)=sqrt(18/26)=sqrt(9/13)