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ласковая1
@ласковая1
December 2021
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помогите решить!!! 1. sin(3x-pi/5)=√2/2 2. sin2x/3=- √3/2 3. sin2x( √x)^2-1/2=0 4. 2cos2( √x)^2-1=0 5. cos4x= √ 5/2 6.cosx+pi=0
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