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Yukinaya
@Yukinaya
August 2022
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Найдите cosα, если sinα = [tex] \sqrt \frac{21}{5} [/tex] и α∈ (π/2 ; π)
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kirichekov
Verified answer
Sin²α+cos²α=1
(√21/5)²+cos²α=1
cos²α=1-21/25
cos²α=4/25
cosα=+-√(4/25)
cosα=+-2/5
по условию α∈(π/2;π), ⇒cosα<0
ответ:
cosα=-2/5
или
cosα=-0,4
1 votes
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Answers & Comments
Verified answer
Sin²α+cos²α=1(√21/5)²+cos²α=1
cos²α=1-21/25
cos²α=4/25
cosα=+-√(4/25)
cosα=+-2/5
по условию α∈(π/2;π), ⇒cosα<0
ответ: cosα=-2/5 или cosα=-0,4