[tex]\displaystyle\bf\\X(t)=\frac{1}{2} t^{2} +5t+11\\\\V(t)=X'(t)=\frac{1}{2} \cdot(t^{2} )'+5\cdot t'+11'=\frac{1}{2} \cdot 2t+5\cdot 1+0=t+5\\\\V(6)=6+5=11\\\\Otvet \ : \ V(6)=11[/tex]
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[tex]\displaystyle\bf\\X(t)=\frac{1}{2} t^{2} +5t+11\\\\V(t)=X'(t)=\frac{1}{2} \cdot(t^{2} )'+5\cdot t'+11'=\frac{1}{2} \cdot 2t+5\cdot 1+0=t+5\\\\V(6)=6+5=11\\\\Otvet \ : \ V(6)=11[/tex]