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TatyanaBergman
@TatyanaBergman
August 2022
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Известно, что cosa= - 5/13 , π‹a‹3π/2.
Вычислите: а) sina, б) sin2a, в) cos2a.
Помогите, пожалуйста.
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kolesnik80
Verified answer
А) sina=-√(1-cos²a)=-√(1 -25/169)=-√(144/169)=-12/13.
б)sin2a=2sina
cosa
=2*(-12/13)*(-5/13)=120/169.
в)cos2a=cos²a-sin²a=(-5/13)² -(-12/13)²=25/169 - 144/169=-119/169.
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TatyanaBergman
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kolesnik80
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Answers & Comments
Verified answer
А) sina=-√(1-cos²a)=-√(1 -25/169)=-√(144/169)=-12/13.б)sin2a=2sinacosa=2*(-12/13)*(-5/13)=120/169.
в)cos2a=cos²a-sin²a=(-5/13)² -(-12/13)²=25/169 - 144/169=-119/169.