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Mulan4ik
@Mulan4ik
July 2022
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(sin2x)/(cos(3pi/2 +x))=1
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darksaid259
Решение.
sin2x = cos(x-3п/2);
2sinx•cosx+sinx=0
sinx•(2cosx+1) =0
1)sinx=0 => x=πn
2)cosx=-½ => x=π±π/3+2πn
1 votes
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Answers & Comments
sin2x = cos(x-3п/2);
2sinx•cosx+sinx=0
sinx•(2cosx+1) =0
1)sinx=0 => x=πn
2)cosx=-½ => x=π±π/3+2πn