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dcheremnyx2011
@dcheremnyx2011
August 2021
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Упростите выражение:
sin(19п/2+x)+cos(7п-x)+cos(7п/2-x)+sin(5п-x)
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kalbim
Verified answer
Sin(19π/2 + x) = sin(10π - π/2 + x) = -sin(π/2 - x) = -cosx
cos(7π - x) = cos(π - x) = -cosx
cos(7π/2 - x) = cos(4π - π/2 - x) = cos(π/2 + x) = -sinx
sin(5π - x) = sin(π - x) = sinx
-cosx - cosx - sinx + sinx = -2cosx
1 votes
Thanks 1
dcheremnyx2011
Помогите пожалуйста: Упростить
(sin10x/cos2x+cos10x/sin2x) / (sin^4x+cos^4x-6sin^2xcos^2x)
dcheremnyx2011
http://znanija.com/task/5323580
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Answers & Comments
Verified answer
Sin(19π/2 + x) = sin(10π - π/2 + x) = -sin(π/2 - x) = -cosxcos(7π - x) = cos(π - x) = -cosx
cos(7π/2 - x) = cos(4π - π/2 - x) = cos(π/2 + x) = -sinx
sin(5π - x) = sin(π - x) = sinx
-cosx - cosx - sinx + sinx = -2cosx
(sin10x/cos2x+cos10x/sin2x) / (sin^4x+cos^4x-6sin^2xcos^2x)