Verified answer

[tex]\displaystyle 0,1u^4v^2-0,8uv^5=\frac{1}{10}u^4v^2-\frac{4}{5}uv^5=\frac{1}{10}uv^2(u^3-8v^3)=\\\frac{1}{10}uv^2(u-2v)(u^2+2uv+4v^2)=0,1uv^2(u-2v)(u^2+2uv+4v^2)[/tex]