Ответ: 25*b^10

Объяснение:

[tex](\frac{6a}{5b} )^2*(\frac{5b^3}{6a} )^4 *(6a)^2 =\frac{6^2*a^2*5^4*b^{12}*6^2*a^2}{5^2*b^2*6^4*a^4} =\frac{5^2*b^{10}}{1} =25b^{10}[/tex]

[tex]\displaystyle\bf\\\Big(\frac{6a}{5b} \Big)^{2} \cdot\Big(\frac{5b^{3} }{6a} \Big)^{4} \cdot(6a)^{2} =\frac{(6a)^{2}\cdot(6a)^{2} }{(5b)^{2} } \cdot\frac{(5b^{3} )^{4} }{(6a)^{4} } =\\\\\\=\frac{(6a)^{4} }{(5b)^{2} } \cdot\frac{(5b^{3} )^{4} }{(6a)^{4} } =\frac{625b^{12} }{25b^{2} } =25b^{12-2} =25b^{10}[/tex]