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edcrfv33
@edcrfv33
August 2022
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20 баллов
(x²+3x)²+4(x+1.5)²-6 = 0
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армения20171
(x²+3x)²+4(x+1,5)²-6=0
(x²+3x)²+4(x²+3x+2,25)-6=0
x²+3x=t
t²+4(t+2,25)-6=0
t²+4t+9-6=0
t²+4t+3=0
D=16-12=4=2²
t=(-4±2)/2
t1=-3;t2=-1
1)x²+3x+3=0
D=9-12=-3<0
x€∅
2)x²+3x+1=0
D=9-4=5
x=(-3±√5)/2
1 votes
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Answers & Comments
(x²+3x)²+4(x²+3x+2,25)-6=0
x²+3x=t
t²+4(t+2,25)-6=0
t²+4t+9-6=0
t²+4t+3=0
D=16-12=4=2²
t=(-4±2)/2
t1=-3;t2=-1
1)x²+3x+3=0
D=9-12=-3<0
x€∅
2)x²+3x+1=0
D=9-4=5
x=(-3±√5)/2