Home
О нас
Products
Services
Регистрация
Войти
Поиск
Петрушка15
@Петрушка15
July 2022
1
3
Report
Найдите корни уравнения cos(3x-pi/2)=1/2, принадлежащие полуинтервалу. ( pi; 3pi/2)
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
Cos(3x-π/2)=sin3x
sin3x=1/2
3x=π/6+2πk⇒x=π/18+2πk/3,k∈z
3x=5π/6+2πk⇒x=5/18+2πk/3,k∈z
1)π<π/18+2πk/3≤3π/2
18<1+12k≤27
17<12k≤26
17/12<k≤26/12
k=1 x=π/18+2π/3=25π/18
2)π<5π/18+2πk/3≤3π/2
18<5+12k≤27
13<12k≤22
13/12<k≤22/12
нет решения
Ответ x=π/18+2πk/3,k∈z;x=5/18+2πk/3,k∈z;x=25π/18
3 votes
Thanks 1
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "2)..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
sin3x=1/2
3x=π/6+2πk⇒x=π/18+2πk/3,k∈z
3x=5π/6+2πk⇒x=5/18+2πk/3,k∈z
1)π<π/18+2πk/3≤3π/2
18<1+12k≤27
17<12k≤26
17/12<k≤26/12
k=1 x=π/18+2π/3=25π/18
2)π<5π/18+2πk/3≤3π/2
18<5+12k≤27
13<12k≤22
13/12<k≤22/12
нет решения
Ответ x=π/18+2πk/3,k∈z;x=5/18+2πk/3,k∈z;x=25π/18