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Lina625
@Lina625
July 2022
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Помогите пожалуйста с алгеброй. 45 баллов ))) Очень очень нужно.. ПОЖАЛУЙСТА
sin[x] * cos[pi/6] - cos[x] * sin[pi/6] <= 1/2
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nKrynka
sin[x] * cos[pi/6] - cos[x] * sin[pi/6] <= 1/2
sin(x -
π/6) ≤ - 1/2
- π - arcsin(-1/2) ≤ (x - π/6) ≤ arcsin(-1/2) + 2πn, n∈Z
- π + π/6 ≤ ( x - π/6) ≤ - π/6 + 2πn, n∈Z
- 5π/6 ≤ ( x - π/6) ≤ - π/6 + 2πn, n∈Z
- 5π/6 + π/6 ≤ x ≤ - π/6 + π/6 + 2πn, n∈Z
-4 π/6 ≤ x ≤ 0 + 2πn, n∈Z
- 2π/3 ≤ x ≤ 2πn, n∈Z
1 votes
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Answers & Comments
sin(x - π/6) ≤ - 1/2
- π - arcsin(-1/2) ≤ (x - π/6) ≤ arcsin(-1/2) + 2πn, n∈Z
- π + π/6 ≤ ( x - π/6) ≤ - π/6 + 2πn, n∈Z
- 5π/6 ≤ ( x - π/6) ≤ - π/6 + 2πn, n∈Z
- 5π/6 + π/6 ≤ x ≤ - π/6 + π/6 + 2πn, n∈Z
-4 π/6 ≤ x ≤ 0 + 2πn, n∈Z
- 2π/3 ≤ x ≤ 2πn, n∈Z