1. tg(π/2 + x) = -1
-ctgx = -1
ctgx = 1
x = arcctg(1) + πn, n ∈ Z
Ответ: x = π/4 + πn, n ∈ Z
2. cosx ≥√3/2
-arccos(√3/2) + 2πn ≤ x ≤ arccos(√3/2) + 2πn, n ∈ Z
Ответ: 5π/6 + 2πn ≤ x ≤ π/6 + 2πn, n ∈ Z
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1. tg(π/2 + x) = -1
-ctgx = -1
ctgx = 1
x = arcctg(1) + πn, n ∈ Z
Ответ: x = π/4 + πn, n ∈ Z
2. cosx ≥√3/2
-arccos(√3/2) + 2πn ≤ x ≤ arccos(√3/2) + 2πn, n ∈ Z
Ответ: 5π/6 + 2πn ≤ x ≤ π/6 + 2πn, n ∈ Z