1) (а+2)(2-а)= (2+а)(2-а)=4-а^2
2)3х2-12=6х-12= 6 (х-2)
3) (2а-b)(2a+b)+b2=4a^2-b^2+2b
4) x (x-1)= (2+x)2
x^2-x=4+2x
x^2-x-4-2x=0
x^2-3x-4=0
x^2+x-4x-4=0
x (x+1)-4(x+1)=0
(x+1)(x-4)=0
x+1=0; x-4=0
x1=-1; x2=4
5) (y+4)2=2y+4•2=2y+8
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Answers & Comments
1) (а+2)(2-а)= (2+а)(2-а)=4-а^2
2)3х2-12=6х-12= 6 (х-2)
3) (2а-b)(2a+b)+b2=4a^2-b^2+2b
4) x (x-1)= (2+x)2
x^2-x=4+2x
x^2-x-4-2x=0
x^2-3x-4=0
x^2+x-4x-4=0
x (x+1)-4(x+1)=0
(x+1)(x-4)=0
x+1=0; x-4=0
x1=-1; x2=4
5) (y+4)2=2y+4•2=2y+8