Ответ:
8u - 6u¹/² + 1
Объяснение:
f'(u)=((2u-u¹/²)²)' = 2(2u - u¹/²) · (2 - 1/(2u¹/²)) =
= 2(4u - 2u¹/²- u¹/² + 1/2) =
= 2(4u - 3u¹/² + 1/2) =
= 8u - 6u¹/² + 1
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Verified answer
Ответ:
8u - 6u¹/² + 1
Объяснение:
f'(u)=((2u-u¹/²)²)' = 2(2u - u¹/²) · (2 - 1/(2u¹/²)) =
= 2(4u - 2u¹/²- u¹/² + 1/2) =
= 2(4u - 3u¹/² + 1/2) =
= 8u - 6u¹/² + 1