f(g(x))' = f'(g(x)) * g'(x)
f(x) = x^n f'(x) = n*x^(n-1)
(√x)' = (x^1/2)' = 1/2*x^-1/2 = 1/2√x
((2u - √u )^2)' = 2(2u - √u)*(2u - √u)' = 2(2u - √u)*(2 - 1/(2√u)) = (2u - √u)*(2 - 1/√u)
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f(g(x))' = f'(g(x)) * g'(x)
f(x) = x^n f'(x) = n*x^(n-1)
(√x)' = (x^1/2)' = 1/2*x^-1/2 = 1/2√x
((2u - √u )^2)' = 2(2u - √u)*(2u - √u)' = 2(2u - √u)*(2 - 1/(2√u)) = (2u - √u)*(2 - 1/√u)