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yumaguzhinaalia
@yumaguzhinaalia
July 2022
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№22. Найдите углы треугольника АВС, если угол В на 400 больше угла А, а угол С в 5 раз больше угла А.
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nikolottorres
Пусть x=уголА, тогда уголВ=х+40°
а уголС=х*5
х+(х+40)+5х=180°
х+х+40+5х=180
2х+5х=180-40
7х=140
х=20
20°=уголА
уголВ=20°+40°=60°
уголС=20°*5=100°
5 votes
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Answers & Comments
а уголС=х*5
х+(х+40)+5х=180°
х+х+40+5х=180
2х+5х=180-40
7х=140
х=20
20°=уголА
уголВ=20°+40°=60°
уголС=20°*5=100°