Решить неравенство:cos(3Π/4)cosx+sin(Π/4)sinx≤-(√3/2). Created by yeschool. algebra-ru

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Решить неравенство:

cos(3Π/4)cosx+sin(Π/4)sinx≤-(√3/2)

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Сos(π-π/4)cosx+sinxsinπ/4≤-√3/2
-cosπ/4cosx+sinπ/4sinx≤-√3/2
-(cosπ/4cosx-sinπ/4sinx)≤-√3/2
cosπ/4cosx-sinπ/4sinx≥√3/2
cos(x+π/4)≥√3/2
-π/6+2πn≤x+π/4≤π/6+2πn
-π/6-π/4+2πn≤x≤π/6-π/4+2πn
-5π/12+2πn≤x≤-π/12+2πn,n∈z

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kak raskryt skobki v dannom sluchae 83x12x 5

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(3-x)=4...

pochemu tolko v 17 veke zavershilos oformlenie krepostnogo prava na rusi

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