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August 2022
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sin(2п +3x)-корень из 3 sin (3п/2+3x)= 0
решите уравнение
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TARTILLO
Verified answer
решите уравнение
Sin(2п +3x)-
√ 3 ·
sin (3п/2+3x)= 0
Sin(3x)-√ 3 ·(-cos 3x)= 0
(1/2)Sin(3x)+(√ 3 /2) ·(cos 3x)=0
cos (3x-π/6)=0
3x-π/6=π/2+πn, n∈Z
x=(π/2+π/6)/3+πn/3, n∈Z
x=2π/9+πn/3, n∈Z
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Answers & Comments
Verified answer
решите уравнение
Sin(2п +3x)-√ 3 ·sin (3п/2+3x)= 0
Sin(3x)-√ 3 ·(-cos 3x)= 0
(1/2)Sin(3x)+(√ 3 /2) ·(cos 3x)=0
cos (3x-π/6)=0
3x-π/6=π/2+πn, n∈Z
x=(π/2+π/6)/3+πn/3, n∈Z
x=2π/9+πn/3, n∈Z