Відповідь:В) 1
[tex]y = \frac{4x - 7}{x^2 + 4} \\y' = \frac{-4 x^2 + 14x +16}{(x^2 + 4)^2 }\\y'(0)= \frac{-4* 0^2 + 14*0 +16}{(0^2 + 4)^2 }=\frac{0+0+16}{0+16} =\frac{16}{16}=1\\ y'(0)=1[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Відповідь:В) 1
[tex]y = \frac{4x - 7}{x^2 + 4} \\y' = \frac{-4 x^2 + 14x +16}{(x^2 + 4)^2 }\\y'(0)= \frac{-4* 0^2 + 14*0 +16}{(0^2 + 4)^2 }=\frac{0+0+16}{0+16} =\frac{16}{16}=1\\ y'(0)=1[/tex]