[tex]\displaystyle \left \{ {{x^2+4x-12\leq 0} \atop {7+3(x+1) > x}} \right. \\\\\left \{ {{x \in [-6,2]} \atop {x > -5}} \right. \\\\x \in (-5,2][/tex]

Verified answer

[tex]\displaystyle\bf\\\left \{ {{x^{2} +4x-12\leq 0} \atop {7+3(x+1) > x}} \right. \\\\\\\left \{ {{(x+6)(x-2)\leq 0} \atop {7+3x+3-x > 0}} \right. \\\\\\\left \{ {{(x+6)(x-2)\leq 0} \atop {2x > -10}} \right. \\\\\\\left \{ {{(x+6)(x-2)\leq 0} \atop {x > -5}} \right.[/tex]

_________[- 6]__________[2]___________

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_______________(- 5)_________________

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Ответ : x ∈ (- 5 ; 2]