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akosh1998
@akosh1998
July 2022
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Решение простейших тригонометрических уравнений:
1)4×sin x/3=0
2)6sin5x-6=0
3)2×sin3x+1=0
4)sinx=√2/2
5)sinx= -√3/2
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nafanya2014
Verified answer
1)4×sin x/3=0 ⇒ sin (x/3)=0 ⇒(x/3)=πk, k∈ Z ⇒ x= 3πk, k∈Z.
2)6sin5x-6=0 ⇒ 6 sin 5x=6 ⇒ sin 5x=1 ⇒ 5x=π/2 + 2πk, k∈Z ⇒ x=π/10 + 2πk/5, k∈Z.
3)2×sin3x+1=0 ⇒ sin 3x=-1/2
4)sinx=√2/2
5)sinx= -√3/2
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Answers & Comments
Verified answer
1)4×sin x/3=0 ⇒ sin (x/3)=0 ⇒(x/3)=πk, k∈ Z ⇒ x= 3πk, k∈Z.2)6sin5x-6=0 ⇒ 6 sin 5x=6 ⇒ sin 5x=1 ⇒ 5x=π/2 + 2πk, k∈Z ⇒ x=π/10 + 2πk/5, k∈Z.
3)2×sin3x+1=0 ⇒ sin 3x=-1/2
4)sinx=√2/2
5)sinx= -√3/2