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LinaMalina110
@LinaMalina110
June 2021
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25 БАЛЛОВ, помогите с математикой
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ПрофиЗнания
2x-π/2=π/6+πn
2x=π/6+π/2+πn
2x=4π/6+πn
2x=2π/3+πn
x=π/3+πn/2
4) 2sin (π+3/4x-3π/2+3/4 x) /2 *cos ( π+3/4x+3π/2-3/4x)/2 =0
2sin( -π/2+6/4x) /2 * cos(5π/2)=0
sin(-π/2+6/4x)=0
-π/2+6/4x=πn
6/4x=π/2+πn
x=π/2*4/6 + 4πn/6
x=π/3+ 2πn/3
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Answers & Comments
2x=π/6+π/2+πn
2x=4π/6+πn
2x=2π/3+πn
x=π/3+πn/2
4) 2sin (π+3/4x-3π/2+3/4 x) /2 *cos ( π+3/4x+3π/2-3/4x)/2 =0
2sin( -π/2+6/4x) /2 * cos(5π/2)=0
sin(-π/2+6/4x)=0
-π/2+6/4x=πn
6/4x=π/2+πn
x=π/2*4/6 + 4πn/6
x=π/3+ 2πn/3