Объяснение:
[tex]\frac{C_9^3*A_{25}^2}{C_{100}^1} +(P_2)^2=\frac{\frac{9!}{(9-3)!*3!}*\frac{25!}{(25-2)!} }{\frac{100!}{(100-1)!*1!} } +(2!)^2=\frac{\frac{6!*7*8*9}{6!*1*2*3} *\frac{23!*24*25}{23!} }{\frac{99!*100}{99!*1} } +(1*2)^2=\\=\frac{7*4*3*24*25}{100} +2^2=504+4=508.[/tex]
Ответ: 508.
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Объяснение:
[tex]\frac{C_9^3*A_{25}^2}{C_{100}^1} +(P_2)^2=\frac{\frac{9!}{(9-3)!*3!}*\frac{25!}{(25-2)!} }{\frac{100!}{(100-1)!*1!} } +(2!)^2=\frac{\frac{6!*7*8*9}{6!*1*2*3} *\frac{23!*24*25}{23!} }{\frac{99!*100}{99!*1} } +(1*2)^2=\\=\frac{7*4*3*24*25}{100} +2^2=504+4=508.[/tex]
Ответ: 508.